Buy equator, sell poles

In an article from Cornell University, a lady astronomer tells us that centrifugal force caused by the rotation of the earth would make a weight at the pole to be 0.5% less on the equator. 200 pounds at the poles would be 199 at the equator. I wonder if anyone has actually done an experiment to see if the math works.

Seems like this would violate any standard of weights and measures. Something in Alaska would weigh more than the same thing in the U. S. Virgin Islands. Is this really true? Does an ingot of aluminum weighing 200 pounds at the poles only weigh 199 pounds at the equator? Or is somebody pulling our leg? I can’t find anything about it in the National Bureau of Standards publication on calibration of weighing devices.

http://curious.astro.cornell.edu/about-us/42-our-solar-system/the-earth/gravity/94-does-your-weight-change-between-the-poles-and-the-equator-intermediate

The standard of weight would have to be used at the poles or the equator, and no difference could be determined. There is no way to do an experiment. The statement that weights are different is essentially meaningless.

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Author: Astrobiology Associates

Senior data analyst at Astrobiology Associates

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